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Mocking Generic Methods

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Hello all,

I want make a test case for "GetInfo" method, in which calling generic method (CreateObject<T>) more than once. Which returns result set based on T passed. But I am able to understand, how to mock CreateObject<T> so that I can return different-different result sets. Kindly let me know.

Thanks
asked by sony
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 (7.2k points)

4 Answers

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Hi Sony,

Just use WhenCalled on CreateObject method few times and each time specify what to return based on the bounded generic argument.
Isolator will know what to return based on the generic argument type bounded type at runtime.

Example. 
var fake = Isolate.Fake.Instance<Foo>();
Isolate.WhenCalled(() => fake.CreateObject<A>()).WillReturn(new A());
Isolate.WhenCalled(() => fake.CreateObject<B>()).WillReturn(new B());

var b = fake.CreateObject<B>();
var a = fake.CreateObject<A>();

Assert.AreEqual(typeof(A), a.GetType());
Assert.AreEqual(typeof(B), b.GetType());
answered by ohad
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 (35.4k points)
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Hi Ohad,

Thanks for your reply, this is pretty helpful. But I am stuck on how to mock private/protected generic method which I can't directly access with fake object. Kindly let me know.

Thanks
answered by sony
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 (7.2k points)
0 votes
Hi Sony,
You should Isolate.NonPublic.WhenCalled together with WithGenericArguments completing statement.

Example: 
var fake = Isolate.Fake.Instance<Foo>();
Isolate.NonPublic.WhenCalled(fake, "CreateObject").WithGenericArguments(typeof (A)).WillReturn(new A());
Isolate.NonPublic.WhenCalled(fake, "CreateObject").WithGenericArguments(typeof (B)).WillReturn(new B());
answered by ohad
Report User
 (35.4k points)
0 votes
Thanks Ohad.
answered by sony
Report User
 (7.2k points)
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