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How Can I fake an instance of an interface?

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Hi,

I have an interface defined with no class implementation. Can I fake an instance of an class which implement this interface or I need to create a dummy class implementing it first?

Thanks.
asked by soguy
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 (1.8k points)

1 Answer

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One of Isolator strengths is creating fake objects from interfaces without any implementation: 
var fake = Isolate.Fake.Instance<IClass>();

Should work just fine
answered by dhelper
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 (11.9k points)
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